计算:(x+5)²-2(x+5)(x+3)+(x+3)²
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计算:(x+5)²-2(x+5)(x+3)+(x+3)²
计算:(x+5)²-2(x+5)(x+3)+(x+3)²
计算:(x+5)²-2(x+5)(x+3)+(x+3)²
(x+5)²-2(x+5)(x+3)+(x+3)²
=(x+5-x-3)²
=2²
=4
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(x+5)²-2(x+5)(x+3)+(x+3)²
=[(x+5)-(x+3)]²
=2²
=4
原式=[x+5-(x+3)]²=2²=4
把 x+5看成a, x+3看成b
(x+5)²-2(x+5)(x+3)+(x+3)²
=[(x+5)-(x+3)]²
=(5-3)平方
=4