已知x/(x²-3x+1)=1,求x²/(x⁴-9x²+1)
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已知x/(x²-3x+1)=1,求x²/(x⁴-9x²+1)
已知x/(x²-3x+1)=1,求x²/(x⁴-9x²+1)
已知x/(x²-3x+1)=1,求x²/(x⁴-9x²+1)
x/(x²-3x+1)=1
x=x²-3x+1
x²+1=4x
两边平方得
x⁴+2x²+1=16x²
x⁴-9x²+1+11x²=16x²
x⁴-9x²+1=16x²-11x²=5x²
于是
x²/(x⁴-9x²+1)
=x²/(5x²)
=1/5