因式分解:2a方+2b方-4ab-2

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因式分解:2a方+2b方-4ab-2
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因式分解:2a方+2b方-4ab-2
因式分解:2a方+2b方-4ab-2

因式分解:2a方+2b方-4ab-2
答:
2a^2+2b^2-4ab-2
=2(a^2-2ab+b^2)-2*1
=2(a-b)^2-2*1^2
=2(a-b+1)(a-b-1)


2a²+2b²-4ab-2
=2(a²-2ab+b²)-2
=2(a-b)²-2
=2[(a-b)²-1]
=2(a-b-1)(a-b+1)

2(a²-2ab+b²-1)
=2[(a-b)²-1]
=2(a-b+1)(a-b-1)

原式=2(a-b)^2-2
=2[(a-b)^2-1]
=2(a-b+1)(a-b-1)