已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值
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![已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值](/uploads/image/z/5896608-24-8.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9D%9E%E9%9B%B6%E5%87%BD%E6%95%B0a.b%E6%BB%A1%E8%B6%B3%EF%BC%9A%28asin%CF%80%2F5%2Bbcos%CF%80%2F5%29%2F%28acos%CF%80%2F5-bsin%CF%80%2F5%29%3Dtan8%CF%80%2F5%E6%B1%82b%2Fa%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A5%E9%9D%9E%E9%9B%B6%E5%87%BD%E6%95%B0a.b%E6%BB%A1%E8%B6%B3%EF%BC%9A%28asin%CF%80%2F5%2Bbcos%CF%80%2F5%29%2F%28acos%CF%80%2F5-bsin%CF%80%2F5%29%3Dtan8%CF%80%2F5%E6%B1%82b%2Fa%E7%9A%84%E5%80%BC)
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已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值
已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值
已知非零函数a.b满足:
(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值
已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值已知非零函数a.b满足:(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5求b/a的值
(asinπ/5+bcosπ/5) = 【(a^2 + b^2)·(1/2)】·sin(π/5 + β) ,其中 ,
cosβ = a / 【(a^2 + b^2)·(1/2)】
sinβ = b / 【(a^2 + b^2)·(1/2)】,
同理 ,(acosπ/5-bsinπ/5) = 【(a^2 + b^2)·(1/2)】·cos(π/5 + β) ,
所以 ,(asinπ/5+bcosπ/5)/(acosπ/5-bsinπ/5)=tan8π/5 = tan(π/5 + β),
因为正切函数的最小正周期 = π ,所以实质上 tanβ = tan(2π/5)
即:b/a = tan(2π/5).