谁给我看看这个数学题咋做[(x+y/x-y)-(x-y/x+y)]*(1/x^2-1/y^2)x=2+根号3y=2-根号3会算还发到这里?
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谁给我看看这个数学题咋做[(x+y/x-y)-(x-y/x+y)]*(1/x^2-1/y^2)x=2+根号3y=2-根号3会算还发到这里?
谁给我看看这个数学题咋做
[(x+y/x-y)-(x-y/x+y)]*(1/x^2-1/y^2)
x=2+根号3
y=2-根号3
会算还发到这里?
谁给我看看这个数学题咋做[(x+y/x-y)-(x-y/x+y)]*(1/x^2-1/y^2)x=2+根号3y=2-根号3会算还发到这里?
word打的,只能图片看了.
把左括号内的式子通分。= =分母就变得很简单。分子照算。
然后右侧看作平方差来逆展回。又有x+y和x-y出现。好解。
由题目可以知道xy=1
之后开始化简[(x+y/x-y)-(x-y/x+y)]*(1/x^2-1/y^2)
={[(x+y)^2-(x-y)^2]/(x^2-y^2)}*[(y^2-x^2)/(x^2*y^2)]
=-[(x+y)^2-(x-y)^2]
=(x-y)^2-(x+y)^2
=(x^2-2xy+y^2)-(x^2+2xy+y^2)
=-4xy=-4
都是口算的不知道算错没 思路是这样的
就是普通的化简题
原式=[(x+y)²-(x-y)²]/(x-y)(x+y)×(1/x-1/y)(1/x+1/y)
=4xy/(x-y)(x+y)×(x-y)/xy×(x+y)/xy
x+y=4,x-y=2根号3,xy=1,代入
可得:原式=4/8根号3×2根号3×4=4
[(x+y/x-y)-(x-y/x+y)]*(1/x^2-1/y^2)
=[(x+y/x-y)-(x-y/x+y)]*(1/x-1/y)*(1/x+1/y)
=[(x+y/x-y)-(x-y/x+y)]*(y-x/xy)*(y+x/xy)
=-(x+y)^2/(x^2y^2)+(x-y)^2/(x^2y^2)
=[(x-y)^2-(x+y)^2]/x^2y^2
=(x-y+x+y)(x-y-x-y)/x^2y^2
=(2x)(-2y)/x^2y^2
=-4/xy
带入x,y值
原式=-4
看不清,自己慢慢算
先化简再求值
原式=-4/xy=-4