已知f(x)是实数集R上的函数,且对任意x属于R,f(x)=f(x+1)+f(x-1)恒成立1.求证f(x)是周期函数2.已知f(3)=2,求f(2004)
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![已知f(x)是实数集R上的函数,且对任意x属于R,f(x)=f(x+1)+f(x-1)恒成立1.求证f(x)是周期函数2.已知f(3)=2,求f(2004)](/uploads/image/z/5904133-61-3.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%29%E6%98%AF%E5%AE%9E%E6%95%B0%E9%9B%86R%E4%B8%8A%E7%9A%84%E5%87%BD%E6%95%B0%2C%E4%B8%94%E5%AF%B9%E4%BB%BB%E6%84%8Fx%E5%B1%9E%E4%BA%8ER%2Cf%28x%29%3Df%28x%2B1%29%2Bf%28x-1%29%E6%81%92%E6%88%90%E7%AB%8B1.%E6%B1%82%E8%AF%81f%28x%29%E6%98%AF%E5%91%A8%E6%9C%9F%E5%87%BD%E6%95%B02.%E5%B7%B2%E7%9F%A5f%283%29%3D2%2C%E6%B1%82f%282004%29)
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