函数f(x)=ax^2+2x+1在(-∞,0)上至少有一个零点,则实数a的取值范围是A.(-∞,0 ) B.(-∞,1] C.(-∞,0)∪(0,1] D.(0,1]
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![函数f(x)=ax^2+2x+1在(-∞,0)上至少有一个零点,则实数a的取值范围是A.(-∞,0 ) B.(-∞,1] C.(-∞,0)∪(0,1] D.(0,1]](/uploads/image/z/5905633-49-3.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3Dax%5E2%2B2x%2B1%E5%9C%A8%28-%E2%88%9E%2C0%29%E4%B8%8A%E8%87%B3%E5%B0%91%E6%9C%89%E4%B8%80%E4%B8%AA%E9%9B%B6%E7%82%B9%2C%E5%88%99%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AFA.%28-%E2%88%9E%2C0+%29+B.%EF%BC%88-%E2%88%9E%2C1%5D+C.%EF%BC%88-%E2%88%9E%2C0%EF%BC%89%E2%88%AA%EF%BC%880%2C1%5D+D.%280%2C1%5D)
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函数f(x)=ax^2+2x+1在(-∞,0)上至少有一个零点,则实数a的取值范围是A.(-∞,0 ) B.(-∞,1] C.(-∞,0)∪(0,1] D.(0,1]
函数f(x)=ax^2+2x+1在(-∞,0)上至少有一个零点,则实数a的取值范围是A.(-∞,0 ) B.(-∞,1] C.(-∞,0)∪(0,1] D.(0,1]
函数f(x)=ax^2+2x+1在(-∞,0)上至少有一个零点,则实数a的取值范围是A.(-∞,0 ) B.(-∞,1] C.(-∞,0)∪(0,1] D.(0,1]
这是选择题,好办
当a=0时 ,函数有零点x=-1/2∈(-∞,0)
可见,a=0肯定是可以的.
==>答案B