有理数a,b,c均不为0,设 x= ││a│/(b+c) +│b│/(c+a) +│c│/(a+b )│,试求x19次方+99x+2000
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 14:19:53
![有理数a,b,c均不为0,设 x= ││a│/(b+c) +│b│/(c+a) +│c│/(a+b )│,试求x19次方+99x+2000](/uploads/image/z/5908409-17-9.jpg?t=%E6%9C%89%E7%90%86%E6%95%B0a%2Cb%2Cc%E5%9D%87%E4%B8%8D%E4%B8%BA0%2C%E8%AE%BE+x%3D+%E2%94%82%E2%94%82a%E2%94%82%2F%28b%2Bc%29+%2B%E2%94%82b%E2%94%82%2F%28c%2Ba%29+%2B%E2%94%82c%E2%94%82%2F%28a%2Bb+%29%E2%94%82%2C%E8%AF%95%E6%B1%82x19%E6%AC%A1%E6%96%B9%2B99x%2B2000)
xQJ0.-Il2BKMYȀ0ADgpQGQSv/xTH{O8fENG^QM9;vӗѲQx5M B)(xbDi{{ў<4-ɀsd~IgYT
]QN@ftm]DKU-RLHI66.KWBbUL#pqy4ykֻx>ӥ-.a*ۊA0 h x#Ex@@j+w[$T
有理数a,b,c均不为0,设 x= ││a│/(b+c) +│b│/(c+a) +│c│/(a+b )│,试求x19次方+99x+2000
有理数a,b,c均不为0,设 x= ││a│/(b+c) +│b│/(c+a) +│c│/(a+b )│,试求x19次方+99x+2000
有理数a,b,c均不为0,设 x= ││a│/(b+c) +│b│/(c+a) +│c│/(a+b )│,试求x19次方+99x+2000
应该有a+b+c=0吧.
a,b,c均不为0,且a+b+c=0,
a+b=-c,b+c=-a,c+a=-b
x=||a|/(b+c)]+[|b|/(a+c)]+[|c|/(a+b)|
=||a|/(-a)+|b|/(-b)+|c|/(-c)|
a+b+c=0,∴abc中必定有一个>0,有一个<0
令a>0,c<0
x=|a/(-a)+|b|/(-b)-c/(-c)|=|-1-|b|/b+c/c|=|-|b|/b|=|±1|=1
x19次方+99x+2000=1+99+2000=2100