曲线积分问题.求∫根号下(2y²+z²)ds,其中积分曲线c为封闭曲线x²+y²+z²=a²过程是I=∫根号下a²dL=a∫dL=a·(2πa)请问2πa是怎么来的,它应该是圆的周长啊,而积分曲线c为封闭
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![曲线积分问题.求∫根号下(2y²+z²)ds,其中积分曲线c为封闭曲线x²+y²+z²=a²过程是I=∫根号下a²dL=a∫dL=a·(2πa)请问2πa是怎么来的,它应该是圆的周长啊,而积分曲线c为封闭](/uploads/image/z/5909076-36-6.jpg?t=%E6%9B%B2%E7%BA%BF%E7%A7%AF%E5%88%86%E9%97%AE%E9%A2%98.%E6%B1%82%E2%88%AB%E6%A0%B9%E5%8F%B7%E4%B8%8B%282y%26%23178%3B%2Bz%26%23178%3B%29ds%2C%E5%85%B6%E4%B8%AD%E7%A7%AF%E5%88%86%E6%9B%B2%E7%BA%BFc%E4%B8%BA%E5%B0%81%E9%97%AD%E6%9B%B2%E7%BA%BFx%26%23178%3B%2By%26%23178%3B%2Bz%26%23178%3B%3Da%26%23178%3B%E8%BF%87%E7%A8%8B%E6%98%AFI%3D%E2%88%AB%E6%A0%B9%E5%8F%B7%E4%B8%8Ba%26%23178%3BdL%3Da%E2%88%ABdL%3Da%C2%B7%282%CF%80a%29%E8%AF%B7%E9%97%AE2%CF%80a%E6%98%AF%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%2C%E5%AE%83%E5%BA%94%E8%AF%A5%E6%98%AF%E5%9C%86%E7%9A%84%E5%91%A8%E9%95%BF%E5%95%8A%2C%E8%80%8C%E7%A7%AF%E5%88%86%E6%9B%B2%E7%BA%BFc%E4%B8%BA%E5%B0%81%E9%97%AD)
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