y=sin(2x+π/6)-2cos(2x+π/3)的最小正周期和最大值 算到y=3根号3/2 *sin2x-1/2 *cos2x 怎么化简
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![y=sin(2x+π/6)-2cos(2x+π/3)的最小正周期和最大值 算到y=3根号3/2 *sin2x-1/2 *cos2x 怎么化简](/uploads/image/z/5911014-30-4.jpg?t=y%3Dsin%282x%2B%CF%80%2F6%29-2cos%282x%2B%CF%80%2F3%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E5%92%8C%E6%9C%80%E5%A4%A7%E5%80%BC+%E7%AE%97%E5%88%B0y%3D3%E6%A0%B9%E5%8F%B73%2F2+%2Asin2x-1%2F2+%2Acos2x+%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80)
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y=sin(2x+π/6)-2cos(2x+π/3)的最小正周期和最大值 算到y=3根号3/2 *sin2x-1/2 *cos2x 怎么化简
y=sin(2x+π/6)-2cos(2x+π/3)的最小正周期和最大值 算到y=3根号3/2 *sin2x-1/2 *cos2x 怎么化简
y=sin(2x+π/6)-2cos(2x+π/3)的最小正周期和最大值 算到y=3根号3/2 *sin2x-1/2 *cos2x 怎么化简
y=sin(2x+π/6)-2cos(2x+π/3)
=√3/2 sin2x+1/2 cos2x -cos2x+√3sinx
=3√3/2sin2x-1/2cos2x
=√28/2sin(2x+X)
最小周期是π 最大值√28/2
y=sin(2x+π/6)-2cos(2x+π/3)
=√3/2 sin2x+1/2 cos2x -cos2x+√3sin2x
=3√3/2sin2x-1/2cos2x
=√28/2(√27/√28sin2x-1/√28cos2x)
=√28/2sin(2x+a)
=√7sin(2x+a) 这里sina=1/√28,cosa=√27/√28
最小周期是π 最大值√7