三角函数 求函数y=cos(πx)∧4 - sin(πx)∧4的最小正周期求函数y=cos(πx)∧4 - sin(πx)∧4的最小正周期方法我也知道,就是想问如果用另外一个方法,化成(1+cos(2πx)∧2)/2+(1-cos(2πx)∧2
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 12:14:15
![三角函数 求函数y=cos(πx)∧4 - sin(πx)∧4的最小正周期求函数y=cos(πx)∧4 - sin(πx)∧4的最小正周期方法我也知道,就是想问如果用另外一个方法,化成(1+cos(2πx)∧2)/2+(1-cos(2πx)∧2](/uploads/image/z/5912518-22-8.jpg?t=%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0+%E6%B1%82%E5%87%BD%E6%95%B0y%3Dcos%EF%BC%88%CF%80x%EF%BC%89%E2%88%A74+-+sin%EF%BC%88%CF%80x%EF%BC%89%E2%88%A74%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E6%B1%82%E5%87%BD%E6%95%B0y%3Dcos%EF%BC%88%CF%80x%EF%BC%89%E2%88%A74+-+sin%EF%BC%88%CF%80x%EF%BC%89%E2%88%A74%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E6%96%B9%E6%B3%95%E6%88%91%E4%B9%9F%E7%9F%A5%E9%81%93%2C%E5%B0%B1%E6%98%AF%E6%83%B3%E9%97%AE%E5%A6%82%E6%9E%9C%E7%94%A8%E5%8F%A6%E5%A4%96%E4%B8%80%E4%B8%AA%E6%96%B9%E6%B3%95%2C%E5%8C%96%E6%88%90%EF%BC%881%2Bcos%282%CF%80x%29%E2%88%A72%EF%BC%89%2F2%2B%EF%BC%881-cos%282%CF%80x%29%E2%88%A72)
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