(sin2α—cos2α)²=()
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(sin2α—cos2α)²=()
(sin2α—cos2α)²=()
(sin2α—cos2α)²=()
(sin2α—cos2α)²=(sin2α)^2-2sin2αcos2α+(cos2α)^2=1-2sin2αcos2α=1-2sin4α
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来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 10:41:21
(sin2α—cos2α)²=()
(sin2α—cos2α)²=()
(sin2α—cos2α)²=()
(sin2α—cos2α)²=(sin2α)^2-2sin2αcos2α+(cos2α)^2=1-2sin2αcos2α=1-2sin4α