已知tanα=-2,求(1+sin2α)/(2cos^2α+sin2α)的值
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已知tanα=-2,求(1+sin2α)/(2cos^2α+sin2α)的值
已知tanα=-2,求(1+sin2α)/(2cos^2α+sin2α)的值
已知tanα=-2,求(1+sin2α)/(2cos^2α+sin2α)的值
==》{(sina+cosa)^2 } / (2cos^2α+sin2α) ={(sina+cosa)^2 } / 2 *cosa *(sina + cosa ) =
(sina + cosa )/2*cosa = 1/2*( tana+1)=-1/2