计算:7x-{-3x+[-2x-(8x-1)]-4}
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 05:34:43
![计算:7x-{-3x+[-2x-(8x-1)]-4}](/uploads/image/z/592294-22-4.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A7x%EF%BC%8D%EF%BD%9B%EF%BC%8D3x%EF%BC%8B%EF%BC%BB%EF%BC%8D2x%EF%BC%8D%EF%BC%888x%EF%BC%8D1%EF%BC%89%EF%BC%BD%EF%BC%8D4%EF%BD%9D)
x){nue^~O1~n ,D~^ 6IEh/~tٚWFWhkUZThj¥4R0 ]M$qC1\@6@L<;lt )~
计算:7x-{-3x+[-2x-(8x-1)]-4}
计算:7x-{-3x+[-2x-(8x-1)]-4}
计算:7x-{-3x+[-2x-(8x-1)]-4}
7x-{-3x+[-2x-(8x-1)]-4}
=7x-[-3x+(-2x-8x+1)-4]
=7x-(-3x-2x-8x+1-4)
=7x-(-13x-3)
=7x+13x+3
=20x+3
20x+3
已知x-3x+1=0,计算2x-3x-7x+2009
x+2/x+3-x+1/x+2=x+8/x+9-x+7/x+8
计算 (x^2-2x+3)(x-1)(x+1)要过程
计算:3x²-[7x-(4x-3)-2x²]
计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?
计算x(x-4)-(x+3)(x-3x+2)-2x(x-2)
计算:7x-{-3x+[-2x-(8x-1)]-4}
计算 x-∞lim(1+1/x)^2x
计算:(3x+1)^2 (3x-1)^2-(2x+1)(-2x+1)
(-x^4)^2-2(x^2)^3×x×x+(-3x)^3×x^5
计算3(2x-1)(x+6)-5(x-3)(x+6)
(2x-2)(x²+3x-1)怎样计算
计算极限x→2,limx²-3x+2/x²-4,
计算x(x+4)+2(x+4)-3x(x+x-1)
计算:(2-5x)/6-x/3
计算(-x^3+2x^2-5)(2x^2-3x+1)
计算(x-1)(x+2)+(-x+1)(x-3)要过程
计算(x-1)(x+2)+(-x+1)(x-3)要过程