若x²-3x+1=0,则x²/x4+x²+1的值为?
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若x²-3x+1=0,则x²/x4+x²+1的值为?
若x²-3x+1=0,则x²/x4+x²+1的值为?
若x²-3x+1=0,则x²/x4+x²+1的值为?
由题意可知:x^2-3x+1=0
即 x^2+1=3x
即 (x^2+1)^2=(3x)^2
即 x^4+2x^2+1=9x^2
所以,x^4+1=7x^2
原式=x^2/(x^4+x^2+1)
=x^2/(7x^2+x^2)
=x^2/(8x^2)
=1/8