已知园M:X2+(y-2)2=1,Q是X轴上的动点,QA,QB分别切圆M于A,B两点 (1)如果|AB|=4倍3分子根2,求直线MQ的方程 (2)求动弦AB的中点的轨迹方程(1)Q(m,0),R=1,M(0,2) 连接QM交AB于P,则MQ垂直平分AB MP=
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![已知园M:X2+(y-2)2=1,Q是X轴上的动点,QA,QB分别切圆M于A,B两点 (1)如果|AB|=4倍3分子根2,求直线MQ的方程 (2)求动弦AB的中点的轨迹方程(1)Q(m,0),R=1,M(0,2) 连接QM交AB于P,则MQ垂直平分AB MP=](/uploads/image/z/5932052-44-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9B%ADM%EF%BC%9AX2%2B%EF%BC%88y-2%EF%BC%892%3D1%2CQ%E6%98%AFX%E8%BD%B4%E4%B8%8A%E7%9A%84%E5%8A%A8%E7%82%B9%2CQA%2CQB%E5%88%86%E5%88%AB%E5%88%87%E5%9C%86M%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9+%EF%BC%881%EF%BC%89%E5%A6%82%E6%9E%9C%7CAB%7C%3D4%E5%80%8D3%E5%88%86%E5%AD%90%E6%A0%B92%2C%E6%B1%82%E7%9B%B4%E7%BA%BFMQ%E7%9A%84%E6%96%B9%E7%A8%8B+%EF%BC%882%EF%BC%89%E6%B1%82%E5%8A%A8%E5%BC%A6AB%E7%9A%84%E4%B8%AD%E7%82%B9%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B%EF%BC%881%EF%BC%89Q%28m%2C0%29%2CR%3D1%2CM%EF%BC%880%2C2%EF%BC%89+%E8%BF%9E%E6%8E%A5QM%E4%BA%A4AB%E4%BA%8EP%2C%E5%88%99MQ%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86AB+MP%3D)
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