2x1-x2+3x3-x4=1 3x1-2x2-2x3+3x4=3 x1-x2-5x3+4x4=2 7x1-5x2-9x3+10x4=8 求基础解析,和通解
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![2x1-x2+3x3-x4=1 3x1-2x2-2x3+3x4=3 x1-x2-5x3+4x4=2 7x1-5x2-9x3+10x4=8 求基础解析,和通解](/uploads/image/z/5932604-20-4.jpg?t=2x1-x2%2B3x3-x4%3D1+3x1-2x2-2x3%2B3x4%3D3+x1-x2-5x3%2B4x4%3D2+7x1-5x2-9x3%2B10x4%3D8+%E6%B1%82%E5%9F%BA%E7%A1%80%E8%A7%A3%E6%9E%90%2C%E5%92%8C%E9%80%9A%E8%A7%A3)
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2x1-x2+3x3-x4=1 3x1-2x2-2x3+3x4=3 x1-x2-5x3+4x4=2 7x1-5x2-9x3+10x4=8 求基础解析,和通解
2x1-x2+3x3-x4=1 3x1-2x2-2x3+3x4=3 x1-x2-5x3+4x4=2 7x1-5x2-9x3+10x4=8 求基础解析,和通解
2x1-x2+3x3-x4=1 3x1-2x2-2x3+3x4=3 x1-x2-5x3+4x4=2 7x1-5x2-9x3+10x4=8 求基础解析,和通解
这样的题目和解二元一次方程一样,将你给的方程依次标记为方程1,2,3,4
用方程1算出:x1=(1+x2-3x3+x4)/2
将这个算式代入剩余的方程2,3,4,得到3个关于x2,x3,x4的方程:
3(1+x2-3x3+x4)/2-2x2-2x3+3x4=3
(1+x2-3x3+x4)/2-x2-5x3+4x4=2
7(1+x2-3x3+x4)/2-5x2-9x3+10x4=8
以此类推,用
3(1+x2-3x3+x4)/2-2x2-2x3+3x4=3
方程算出:x2= -13x3+9x4-3
代入
(1+x2-3x3+x4)/2-x2-5x3+4x4=2
7(1+x2-3x3+x4)/2-5x2-9x3+10x4=8
然后就变成x3,x4的二元一次方程了,这个就简单了
这个方法就叫做消元法,解多元方程的通用方法
这里有说明:
http://baike.baidu.com/view/6093994.htm
用初等行变换来解下列线性方程组(1)2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6(2) x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5(3) x1-x2+x3-x4=1 x1-x2-x3+x4=0 x1-x2-2x3+2x4=-1/2
解方程组X1-2x2+3x3-x4=1,3x1-x2+5x3-3x4=2,2x1+x2+2x3-2x4=3
写出方程组2*x1+x2-x3+x4=1,x1+2*x2+x3-x4=2,x1+x2+2*x3+x4=3的通解?
求非齐次线方程组的通解 :2x1+x2-x3+x4=1 x1+2x2+x3-x4=2 x1+x2+2x3+x4=3
具体写出方程组:2x1+x2-x3+x4=1;x1+2x2+x3-x4=2;x1+x2+2x3+x4=3的通解
解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2
x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1
非齐次线性方程组求解.x1+x2+2x3+3x4=1 2x1+3x2+5x3+2x4=-3 3x1-x2-x3-2x4=-4 3x1+5x2+2x3-2x4=-10
求非齐次线性方程组的通解x1+3x2+5x3-4x4=1x1+3x2+2x3-2x4+x5=-1x1-2x2+x3-x4-x5=3x1+2x2+x3-x4-x5=3
讨论2X1+X2-X3+X4=1 3X1-2X2+2X3-3X4=2 5X1+X2-X3+2X4=-1 2X1-X2+X3-3X4=4的解的情况
X1-X2-3X3+X4=1 X1-X2+2X3-X4=3 2X1-2X2-11X3+4X4=0 4X1-4X2+3X3-2X4=10 用消元法 解线性方程组
求方程组X1-3X2-2X3-X4=1 3X1-8X2-4X3-X4=0 -2X1+X2-4X3+2X4=1 -X1-2X2-6X3+X4=2的解
求线性方程组{X1-3x2-2x3-X4=1;3X1-8X2-4X3-X4=0;-2X1+X2-4X3+2X4=1;-X1-2X2-6X3+X4=2的一般解.
求线性方程组x1-3x2-2x3-x4=1,3x1-8x2-4x3-x4,-2x1+x2-4x3+2x4=1,-x1-2x2-6x3+x4=
{2X1 -X2 -X3 +X4 = 2{X1 +X2 -2X3 +X4 = 2{4X1 -6X2 +2X3 -2X4 = 4{X1 +4X2 -3X3 +2X4 = 1
x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x1,x2,x3,x4,x5
线性方程组求解,x1+2x2+x3-x4=1 3x1+6x2-x3-3x4=0
线性方程组 X1+X2+X3+X4=0,2X1+X2+X3+2X4=0,3X1+2X2+4X3+4=1