(x²+y²)-x²y²3ax²-3ay四次方p四次方-1
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 01:28:32
![(x²+y²)-x²y²3ax²-3ay四次方p四次方-1](/uploads/image/z/5934259-19-9.jpg?t=%28x%26%23178%3B%2By%26%23178%3B%EF%BC%89-x%26%23178%3By%26%23178%3B3ax%26%23178%3B-3ay%E5%9B%9B%E6%AC%A1%E6%96%B9p%E5%9B%9B%E6%AC%A1%E6%96%B9-1)
x)ӨPS64֮tB"ƉPqbٳYl8K&HʰB1RΆ+.-0!P2{:*⌴+~ giTk"@55*tAďq&Pj
6Qhb`$_\g
0D UAE'2 $X醍/|`{zuL|}ϧxٜ&>lҗ Eԋ勩@({n
VP
(x²+y²)-x²y²3ax²-3ay四次方p四次方-1
(x²+y²)-x²y²
3ax²-3ay四次方
p四次方-1
(x²+y²)-x²y²3ax²-3ay四次方p四次方-1
(x²+y²)-x²y²
=(x^2+y^2+xy)(x^2+y^2-xy)
3ax²-3ay^4
=3a(x^2-y^4)
=3a(x+y^2)(x-y^2)
p^4-1
=(p^2+1)(p^2-1)
=(p^2+1)(p+1)(p-1)
(x²+y²)-x²y²
=(x²+y²+xy)(x²+y²-xy)
3ax²-3ay^4
=3a(x²-y^4)
=3a(x+y²)(x-y²)
p^4-1
=(p²+1)(p²-1)
=(p²+1)(p+1)(p-1)
就这样把,我已经用了最少的步骤了
解(x²+y²)-x²y²
=(x^2+y^2+xy)(x^2+y^2-xy)
解3ax²-3ay^4
=3a(x^2-y^4)
=3a(x+y^2)(x-y^2)
解p^4-1
=(p^2+1)(p^2-1)
=(p^2+1)(p+1)(p-1)