x y互为相反数 m n互为倒数 a的绝对值=1 求a的2次方-(x+y+mn)xa+(x+y)2011次方= 求大师解决
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![x y互为相反数 m n互为倒数 a的绝对值=1 求a的2次方-(x+y+mn)xa+(x+y)2011次方= 求大师解决](/uploads/image/z/594314-26-4.jpg?t=x+y%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0+m+n%E4%BA%92%E4%B8%BA%E5%80%92%E6%95%B0+a%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%3D1+%E6%B1%82a%E7%9A%842%E6%AC%A1%E6%96%B9-%28x%2By%2Bmn%29xa%2B%28x%2By%292011%E6%AC%A1%E6%96%B9%3D+%E6%B1%82%E5%A4%A7%E5%B8%88%E8%A7%A3%E5%86%B3)
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