1.已知a+x²=2007,b+x²=2008,c+x²=2009,abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c2.设abc=1,求分式a/ab+a+1+b/bc+b+1+c/ca+c+1的值
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![1.已知a+x²=2007,b+x²=2008,c+x²=2009,abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c2.设abc=1,求分式a/ab+a+1+b/bc+b+1+c/ca+c+1的值](/uploads/image/z/5964463-55-3.jpg?t=1.%E5%B7%B2%E7%9F%A5a%2Bx%26sup2%3B%3D2007%2Cb%2Bx%26sup2%3B%3D2008%2Cc%2Bx%26sup2%3B%3D2009%2Cabc%3D6012%E6%B1%82a%2Fbc%2Bb%2Fca%2Bc%2Fab-1%2Fa-1%2Fb-1%2Fc2.%E8%AE%BEabc%3D1%2C%E6%B1%82%E5%88%86%E5%BC%8Fa%2Fab%2Ba%2B1%2Bb%2Fbc%2Bb%2B1%2Bc%2Fca%2Bc%2B1%E7%9A%84%E5%80%BC)
1.已知a+x²=2007,b+x²=2008,c+x²=2009,abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c2.设abc=1,求分式a/ab+a+1+b/bc+b+1+c/ca+c+1的值
1.已知a+x²=2007,b+x²=2008,c+x²=2009,abc=6012
求a/bc+b/ca+c/ab-1/a-1/b-1/c
2.设abc=1,求分式a/ab+a+1+b/bc+b+1+c/ca+c+1的值
1.已知a+x²=2007,b+x²=2008,c+x²=2009,abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c2.设abc=1,求分式a/ab+a+1+b/bc+b+1+c/ca+c+1的值
原式=(a/bc-1/a)+(b/ca-1/b)+(c/ab-1/c)
=(a²-bc)/abc+(b²-ac)/abc+(c²-ab)/abc
=(a²+b²+c²-bc-ac-ab)/abc
=[1/2(a-b)²+1/2(b-c)²+1/2(a-c)²]/abc
a+x²=2007,b+x²=2008,c+x²=2009
a+x²-b-x²=2007-2008
a-b=-1
a+x²-c-x²=2007-2009
a-c=-2
b+x²-c-x²=2008-2009
b-c=-1
abc=6012
原式=[1/2(-1)²+1/2(-1)²+1/2(-2)²]/6012
=3/6012
=1/2004
a+x²=2007,b+x²=2008,c+x²=2009 得出 a+2=b+1=c
a/bc+b/ca+c/ab-1/a-1/b-1/c
=(a²+b²+c²-ab-ac-bc)/abc 把a=c-2,b=c-1带入化简得
原式=3/abc=1/2004
第二道是不是少括号了?
a/bc+b/ca+c/ab-1/a-1/b-1/c
=((a-c)2+(b-c)2+(a-b)2)/2abc
=1/2004
1.原式=(a/bc-1/a)+(b/ca-1/b)+(c/ab-1/c)
=(a²-bc)/abc+(b²-ac)/abc+(c²-ab)/abc
=(a²+b²+c²-bc-ac-ab)/abc
=[1/2(a-b)²+1/2(b-c)&su...
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1.原式=(a/bc-1/a)+(b/ca-1/b)+(c/ab-1/c)
=(a²-bc)/abc+(b²-ac)/abc+(c²-ab)/abc
=(a²+b²+c²-bc-ac-ab)/abc
=[1/2(a-b)²+1/2(b-c)²+1/2(a-c)²]/abc
∵a+x²=2007,b+x²=2008,c+x²=2009
∴a+x²-b-x²=2007-2008
∴a-b=-1
∴a+x²-c-x²=2007-2009
∴a-c=-2
∴b+x²-c-x²=2008-2009
∴b-c=-1
∵abc=6012
∴原式=[1/2(-1)²+1/2(-1)²+1/2(-2)²]/6012
=3/6012
=1/2004
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