matlab新手问题h=0.1;t=0:h:1;N=length(t);y=ones(1,N);for k=2:N;y(1,k)=y(1,k-1)+h*(y(1,k-1)-2.*t/y(1,k-1))end问题是Subscripted assignment dimension mismatch.
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![matlab新手问题h=0.1;t=0:h:1;N=length(t);y=ones(1,N);for k=2:N;y(1,k)=y(1,k-1)+h*(y(1,k-1)-2.*t/y(1,k-1))end问题是Subscripted assignment dimension mismatch.](/uploads/image/z/5971448-56-8.jpg?t=matlab%E6%96%B0%E6%89%8B%E9%97%AE%E9%A2%98h%3D0.1%3Bt%3D0%3Ah%3A1%3BN%3Dlength%28t%29%3By%3Dones%281%2CN%29%3Bfor+k%3D2%3AN%3By%281%2Ck%29%3Dy%281%2Ck-1%29%2Bh%2A%28y%281%2Ck-1%29-2.%2At%2Fy%281%2Ck-1%29%29end%E9%97%AE%E9%A2%98%E6%98%AFSubscripted+assignment+dimension+mismatch.)
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matlab新手问题h=0.1;t=0:h:1;N=length(t);y=ones(1,N);for k=2:N;y(1,k)=y(1,k-1)+h*(y(1,k-1)-2.*t/y(1,k-1))end问题是Subscripted assignment dimension mismatch.
matlab新手问题
h=0.1;
t=0:h:1;
N=length(t);
y=ones(1,N);
for k=2:N;
y(1,k)=y(1,k-1)+h*(y(1,k-1)-2.*t/y(1,k-1))
end
问题是Subscripted assignment dimension mismatch.
matlab新手问题h=0.1;t=0:h:1;N=length(t);y=ones(1,N);for k=2:N;y(1,k)=y(1,k-1)+h*(y(1,k-1)-2.*t/y(1,k-1))end问题是Subscripted assignment dimension mismatch.
y(1,k)=y(1,k-1)+h*(y(1,k-1)-2.*t/y(1,k-1))
这句话的问题
数组维度不匹配.
等号左边是一个标量,右边计算得到的是一个1*11的向量.