焦点在x轴上的椭圆离心率为二分之根号三,并且椭圆与(x-2)^+(y-1)^=5/2交于A,B两点,线段AB的长等于圆的直径1,求直线AB的方程2,求椭圆的方程
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![焦点在x轴上的椭圆离心率为二分之根号三,并且椭圆与(x-2)^+(y-1)^=5/2交于A,B两点,线段AB的长等于圆的直径1,求直线AB的方程2,求椭圆的方程](/uploads/image/z/602062-70-2.jpg?t=%E7%84%A6%E7%82%B9%E5%9C%A8x%E8%BD%B4%E4%B8%8A%E7%9A%84%E6%A4%AD%E5%9C%86%E7%A6%BB%E5%BF%83%E7%8E%87%E4%B8%BA%E4%BA%8C%E5%88%86%E4%B9%8B%E6%A0%B9%E5%8F%B7%E4%B8%89%2C%E5%B9%B6%E4%B8%94%E6%A4%AD%E5%9C%86%E4%B8%8E%28x-2%29%5E%2B%28y-1%29%5E%3D5%2F2%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E7%BA%BF%E6%AE%B5AB%E7%9A%84%E9%95%BF%E7%AD%89%E4%BA%8E%E5%9C%86%E7%9A%84%E7%9B%B4%E5%BE%841%2C%E6%B1%82%E7%9B%B4%E7%BA%BFAB%E7%9A%84%E6%96%B9%E7%A8%8B2%2C%E6%B1%82%E6%A4%AD%E5%9C%86%E7%9A%84%E6%96%B9%E7%A8%8B)
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