先化简再求值1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1 其中X是最小的非负整数.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/06 11:57:25
![先化简再求值1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1 其中X是最小的非负整数.](/uploads/image/z/603156-12-6.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC1-%EF%BC%881-+1%2F1-X%EF%BC%89%26%23178%3B%C3%B7+X%26%23178%3B-X%2B1%2FX%26%23178%3B-2X%2B1+%E5%85%B6%E4%B8%ADX%E6%98%AF%E6%9C%80%E5%B0%8F%E7%9A%84%E9%9D%9E%E8%B4%9F%E6%95%B4%E6%95%B0.)
先化简再求值1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1 其中X是最小的非负整数.
先化简再求值1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1 其中X是最小的非负整数.
先化简再求值1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1 其中X是最小的非负整数.
1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1
=1-[(1-x-1)/(1-x)]² ×(x-1)²/(x²-x+1)
=1-x²/(x-1)²×(x-1)²/(x²-x+1)
=1-ײ/(x²-x+1)
=(x²-x+1-x²)/(x²-x+1)
=(1-x)/(x²-x+1)
当x=0时
原式=1
1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1=1-[(1-x-1)/1-x]/[(x^2-x+1)/(x-1)^2]
=1-[x/(x-1)] *[(x-1)^2/(x^2-x+1)]
=1-[x/(x^2-x+1)]
=(x^2-x+1+x)/(x^2-x-1)
=(x^2+1)/(x^2-x-1)
由题意x=0...
全部展开
1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1=1-[(1-x-1)/1-x]/[(x^2-x+1)/(x-1)^2]
=1-[x/(x-1)] *[(x-1)^2/(x^2-x+1)]
=1-[x/(x^2-x+1)]
=(x^2-x+1+x)/(x^2-x-1)
=(x^2+1)/(x^2-x-1)
由题意x=0
原式=-1
有什么不明白可以继续问,随时在线等。
如果我的回答对你有帮助,请及时选为满意答案,谢谢~~
收起
1-(1- 1/1-X)²÷ X²-X+1/X²-2X+1
=1-[x²/(1-x)² ]÷(x²-x+1)/(1-x)²
=1-(x²/x²-x+1)
=(x-1)/(x²-x+1)
∵x是最小的非负整数
∴x=0
∴原式=(-1)/1
=-1
1-(x-1/1-x)^2÷x^2-x+1/x^2-2x+1,其中x^2-x+5=0
=1-(x-x²-1)²/(1-x)²÷(x²-x+1)/(x-1)²
=1-(x²-x+1)²/(x²-x+1)
=1-x²+x-1
=-(x²-x)
=-(-5)
=5