(1)-18÷(-3)²+5×(-1/2)³-(-15)÷5(2)已知有理数a、b、c在数轴上的位置如图所示,且丨a丨=丨b丨1.求a^5+b^5的值2.化简丨a丨-丨a+b丨-丨c-a丨+丨c-b丨+丨ac丨-丨-2b丨
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 03:31:26
![(1)-18÷(-3)²+5×(-1/2)³-(-15)÷5(2)已知有理数a、b、c在数轴上的位置如图所示,且丨a丨=丨b丨1.求a^5+b^5的值2.化简丨a丨-丨a+b丨-丨c-a丨+丨c-b丨+丨ac丨-丨-2b丨](/uploads/image/z/603299-11-9.jpg?t=%281%29-18%C3%B7%EF%BC%88-3%EF%BC%89%26%23178%3B%2B5%C3%97%EF%BC%88-1%2F2%EF%BC%89%26%23179%3B-%EF%BC%88-15%EF%BC%89%C3%B75%EF%BC%882%EF%BC%89%E5%B7%B2%E7%9F%A5%E6%9C%89%E7%90%86%E6%95%B0a%E3%80%81b%E3%80%81c%E5%9C%A8%E6%95%B0%E8%BD%B4%E4%B8%8A%E7%9A%84%E4%BD%8D%E7%BD%AE%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E4%B8%94%E4%B8%A8a%E4%B8%A8%3D%E4%B8%A8b%E4%B8%A81.%E6%B1%82a%5E5%2Bb%5E5%E7%9A%84%E5%80%BC2.%E5%8C%96%E7%AE%80%E4%B8%A8a%E4%B8%A8-%E4%B8%A8a%2Bb%E4%B8%A8-%E4%B8%A8c-a%E4%B8%A8%2B%E4%B8%A8c-b%E4%B8%A8%2B%E4%B8%A8ac%E4%B8%A8-%E4%B8%A8-2b%E4%B8%A8)
(1)-18÷(-3)²+5×(-1/2)³-(-15)÷5(2)已知有理数a、b、c在数轴上的位置如图所示,且丨a丨=丨b丨1.求a^5+b^5的值2.化简丨a丨-丨a+b丨-丨c-a丨+丨c-b丨+丨ac丨-丨-2b丨
(1)-18÷(-3)²+5×(-1/2)³-(-15)÷5
(2)已知有理数a、b、c在数轴上的位置如图所示,且丨a丨=丨b丨
1.求a^5+b^5的值
2.化简丨a丨-丨a+b丨-丨c-a丨+丨c-b丨+丨ac丨-丨-2b丨
(1)-18÷(-3)²+5×(-1/2)³-(-15)÷5(2)已知有理数a、b、c在数轴上的位置如图所示,且丨a丨=丨b丨1.求a^5+b^5的值2.化简丨a丨-丨a+b丨-丨c-a丨+丨c-b丨+丨ac丨-丨-2b丨
(1) -18÷(-3)²+5×(-1/2)³-(-15)÷5
=-2-5/8+3=3/8
(2)a^5+b^5=a^5+(-a)^5=0
丨a丨-丨a+b丨-丨c-a丨+丨c-b丨+丨ac丨-丨-2b丨
=-a-0-(a-c)+(-c+b)+ac-2b
=ac-b
=ac-a
=(c-1)a
(1) -18÷(-3)²+5×(-1/2)³-(-15)÷5
=-18÷9+5×(-1/8)-(-3)
=-2+(-5/8)+3
=3/8
(2)因丨a丨=丨b丨,故a=-b,所以有:a^5+b^5=(-b)^5+b^5=(b-b)^5=0
因丨a丨=丨b丨,故b=-a,a是负数,b是正数,故,丨a丨=-a=b...
全部展开
(1) -18÷(-3)²+5×(-1/2)³-(-15)÷5
=-18÷9+5×(-1/8)-(-3)
=-2+(-5/8)+3
=3/8
(2)因丨a丨=丨b丨,故a=-b,所以有:a^5+b^5=(-b)^5+b^5=(b-b)^5=0
因丨a丨=丨b丨,故b=-a,a是负数,b是正数,故,丨a丨=-a=b,丨b丨=b,且有c<0,丨c丨=-c,丨c丨>b,所以有:
丨a丨-丨a+b丨-丨c-a丨+丨c-b丨+丨ac丨-丨-2b丨
=b-丨b+b丨-丨c-(-b)丨+(-c)-b+ac-2b
=b-2b-丨b+c丨-c-b+(-b)c-2b
=-4b-(-c-b)-c-bc
=-4b+c*c+bc-c-bc
=4b+c*c-c
收起