作业帮1x2/1+2x3/1+3x4/1+…+2008x2009/1=?
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1x2/1+2x3/1+3x4/1+…+2008x2009/1=?
1x2/1+2x3/1+3x4/1+…+2008x2009/1=?
1x2/1+2x3/1+3x4/1+…+2008x2009/1=?
1x2分之1+2X3分之1+3X4分之1+.+2007X2008分之1+12008X2009分之1
=1-(1/2)+(1/2)-(1/3)+(1/3)-(1/4)+...+(1/2007)-(1/2008)+(1/2008)-(1/2009)
=1-(1/2009)
=2008/2009
1x2分之1=1/(1*2)=1-(1/2)
2X3分之1=1/(2*3)=(1/2)-(1/3)
3X4分之1=1/(3*4)=(1/3)-(1/4)
................
1x2/1+2x3/1+3x4/1+…+2008x2009/1
=1-1/2+1/2-1/3+1/3-1/4+...+1/2008-1/2009
=1-1/2009
=2008/2009;
1X2+2x3+3x4+……+2013x2014
用克拉默法则解下列方程组 x1-2x2+3x3-4x4=4 x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3x1-2x2+3x3-4x4=4x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3
因式分解：x4+x3+2x2 +x+1
解方程组X1-2x2+3x3-x4=1,3x1-x2+5x3-3x4=2,2x1+x2+2x3-2x4=3
x1+5x2-x3-x4=-1x1-2x2+x3+3x4=33x1+8x2-x3+x4=1
写出方程组2*x1+x2-x3+x4=1,x1+2*x2+x3-x4=2,x1+x2+2*x3+x4=3的通解?
求非齐次线方程组的通解 ：2x1+x2-x3+x4=1 x1+2x2+x3-x4=2 x1+x2+2x3+x4=3
具体写出方程组：2x1+x2-x3+x4=1;x1+2x2+x3-x4=2;x1+x2+2x3+x4=3的通解
解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2
用初等行变换来解下列线性方程组（1）2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6(2) x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5(3) x1-x2+x3-x4=1 x1-x2-x3+x4=0 x1-x2-2x3+2x4=-1/2
1X2+2X3+3X4+.NX(N+1)
1X2+2X3+3X4+.NX(N+1)规律
1x2+2x3+3x4+.+2011x2012
1x2+2x3+3x4+4x5+.+15x16
1x2+2x3+3x4+.+100x101=
1x2+2x3+3x4+.+100x101=?结果
1x1!+2x2!+3x3!+4x4!.nxn!
1x2+2x3+3x4+.+19x20