(1/x-1/2)÷(1-x^2+4/4x)
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(1/x-1/2)÷(1-x^2+4/4x)
(1/x-1/2)÷(1-x^2+4/4x)
(1/x-1/2)÷(1-x^2+4/4x)
(1/x-1/2)÷(1-x^2+4/4x)=(1/x-1/2)/(1-x^2+1/x)=[(2-x)/(2x)]/[(x-x^3+1)/x]=[(2-x)/(2x)]*[x/(x-x^3+1)]={}[(x-2)/2]*[1/(x^3-x-1)]
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一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
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