运用整式乘法公式 0.345^2 +1.345^2-0.345*2.69 .计算:(y-x)^3*(x-y)^m-(x-y)^m+2*(y-x)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 19:47:19
运用整式乘法公式 0.345^2 +1.345^2-0.345*2.69 .计算:(y-x)^3*(x-y)^m-(x-y)^m+2*(y-x)
xRn@&TAGA(BroA*(ԐҀH۔VI*UvAur/0]BU%'g޼7o z/?ol|`/Bem~hȒ ɮ?вQkLJ6}m6"4ȕc>Zq JqoYlP_~1q}o^Z4|NxHyO~:)Λ.u6T?)L%B68"FA% .pָ kjAj*3i%`fA3g+/:.4#5=9[fLV8cO5#Y$޹{uZ= :S.l%iQ|U1!M9JϮ o> kK.21Y?dx0V!OkBkht .L[[`T*OD {Q$#K%DH<;\2UY1eI%1 D_J`kEE5-vkʖV)kPѦ!vrVJ

运用整式乘法公式 0.345^2 +1.345^2-0.345*2.69 .计算:(y-x)^3*(x-y)^m-(x-y)^m+2*(y-x)
运用整式乘法公式 0.345^2 +1.345^2-0.345*2.69 .计算:(y-x)^3*(x-y)^m-(x-y)^m+2*(y-x)

运用整式乘法公式 0.345^2 +1.345^2-0.345*2.69 .计算:(y-x)^3*(x-y)^m-(x-y)^m+2*(y-x)
(1)(x-a)²=x²-2ax+a²,此时等于代数式x²-8x+2b
可知-2a=-8,a=4;a²=16=2b,b=8
因此b-ab=8-32=-24
(2)用一个边长为a的正方形和四个长方形得到的面积为a²+4ab,需要再用边长为b的正方形拼成大正方形,即a²+4ab+_b²=( )²,显然根据代数式前两项可得(a+2b)²=a²+4ab+4b²
因此需要4个边长为b的正方形,拼成一个边长为a+2b的大正方形
①x^2-8x+2b=(x-a)^2=x^2-2ax+a^2,对应系数相等,则8=2a,2b=a^2,所以a=4,b=8,则b-ab=-24.

0.345^2 +1.345^2-0.345*2.69
=0.345^2-2*0.345*1.345+1.345^2
=(1.345-0.345)^2
=1
(y-x)^3*(x-y)^m-(x-y)^m+2*(y-x)
=-(x-y)^3(x-y)^m-(x-y)^m-2(x-y)
=-(x-y)[(x-y)^(m+2)+(x-y)^(m-1)+2]

0.345^2 +1.345^2-0.345*2.69
=0.345^2 +1.345^2-2*0.345*1.345
=(0.345-1.345)^2
=(-1)^2
=1
(y-x)^3*(x-y)^m-(x-y)^(m+2)*(y-x)
=0

0.345^2 +1.345^2-0.345*2.69
=0.345^2 +1.345^2-2*0.345*1.345
=(0.345-1.345)^2
=(-1)^2
=1
(y-x)^3*(x-y)^m-(x-y)^(m+2)*(y-x)
=- (x-y)^3*(x-y)^m+(x-y)^(m+2)*(x-y)
=- (x-y)^(3+m)+(x-y)^(m+2+1)
=- (x-y)^(3+m)+(x-y)^(m+3)
=0