解下列方程:(1)(3y+5/3y-6)=1/2+(5y-4/2y-4)(2)(1/x+4)-(1/x+7)=(1/x+3)-(1/x+6)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 03:45:28
解下列方程:(1)(3y+5/3y-6)=1/2+(5y-4/2y-4)(2)(1/x+4)-(1/x+7)=(1/x+3)-(1/x+6)
xPN0~ޙT.(%ޘP20+ xFD}ʔW*baݹC[ mݾn;v ݒ*1Jqק) Lń7K@~W_0UYӐ~xطmO$7^ɰ߄FtV  R^C@0B2c(gۡ۬62I\2ew; s4k70aRt

解下列方程:(1)(3y+5/3y-6)=1/2+(5y-4/2y-4)(2)(1/x+4)-(1/x+7)=(1/x+3)-(1/x+6)
解下列方程:
(1)(3y+5/3y-6)=1/2+(5y-4/2y-4)
(2)(1/x+4)-(1/x+7)=(1/x+3)-(1/x+6)

解下列方程:(1)(3y+5/3y-6)=1/2+(5y-4/2y-4)(2)(1/x+4)-(1/x+7)=(1/x+3)-(1/x+6)
(1)两边同乘以6(y-2),得
2(3y+5)=3(y-2)+3(5y-4)
6y+10=18y-18
12y=28
y=7/3
(2) 通分:3/((x+4)(x+7))=3/((x+3)(x+6))
(x+4)(x+7)=(x+3)(x+6)
11x+28=9x+18
2x= -10
x= -5