化简:[(x+1)/(x²-1)]×(x-3)已知ab=﹣1,a+b=2,则式子b/a+a/b=?(上面两个都要答案)

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 20:13:10
化简:[(x+1)/(x²-1)]×(x-3)已知ab=﹣1,a+b=2,则式子b/a+a/b=?(上面两个都要答案)
x){3{fEkThjkT)j~OG=Ooz>ib IN5O;f>t$DD$[{';^]dǒ';VlbYS-дI*'>ZjX_`gCoA[ QTqx:2ak)fB0h$BlNК@ODE2@N,TZ;I:f6yv0s4".4$lޜ';vVs.

化简:[(x+1)/(x²-1)]×(x-3)已知ab=﹣1,a+b=2,则式子b/a+a/b=?(上面两个都要答案)
化简:[(x+1)/(x²-1)]×(x-3)
已知ab=﹣1,a+b=2,则式子b/a+a/b=?(上面两个都要答案)

化简:[(x+1)/(x²-1)]×(x-3)已知ab=﹣1,a+b=2,则式子b/a+a/b=?(上面两个都要答案)
:[(x+1)/(x²-1)]×(x-3)
=(x+1)/(x+1)(x-1)×(x-3)
=1/(x-1)×(x-3)
=(x-3)/(x-1)
b/a+a/b=(a²+b²)/ab=[(a²+2ab+b²)-2ab]/ab=[(a+b)²-2ab]/ab=(4+2)/(-1)=-6

(X-3)/(X-1)

化简结果为X-3/x-1
b/a+a/b=-6