初三相似三角形证明题如图,△ABC中,∠BAC=90°,AD是斜边BC的中线,CE⊥AD于点E,CE的延长线交边AB于点E,CE的延长线交边AB于点F,若AF=1,BE=3,求线段DE的长
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![初三相似三角形证明题如图,△ABC中,∠BAC=90°,AD是斜边BC的中线,CE⊥AD于点E,CE的延长线交边AB于点E,CE的延长线交边AB于点F,若AF=1,BE=3,求线段DE的长](/uploads/image/z/6082270-70-0.jpg?t=%E5%88%9D%E4%B8%89%E7%9B%B8%E4%BC%BC%E4%B8%89%E8%A7%92%E5%BD%A2%E8%AF%81%E6%98%8E%E9%A2%98%E5%A6%82%E5%9B%BE%2C%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%3D90%C2%B0%2CAD%E6%98%AF%E6%96%9C%E8%BE%B9BC%E7%9A%84%E4%B8%AD%E7%BA%BF%2CCE%E2%8A%A5AD%E4%BA%8E%E7%82%B9E%2CCE%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4%E8%BE%B9AB%E4%BA%8E%E7%82%B9E%2CCE%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4%E8%BE%B9AB%E4%BA%8E%E7%82%B9F%2C%E8%8B%A5AF%3D1%2CBE%3D3%2C%E6%B1%82%E7%BA%BF%E6%AE%B5DE%E7%9A%84%E9%95%BF)
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