如图,在RT△ABC中,已知∠C=90°,AC=8,∠A的平分线AD=(16根号3)/3,求∠B及BC的值用tan,cos,sin来解
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![如图,在RT△ABC中,已知∠C=90°,AC=8,∠A的平分线AD=(16根号3)/3,求∠B及BC的值用tan,cos,sin来解](/uploads/image/z/612764-44-4.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8RT%E2%96%B3ABC%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5%E2%88%A0C%3D90%C2%B0%2CAC%3D8%2C%E2%88%A0A%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BFAD%3D%2816%E6%A0%B9%E5%8F%B73%29%2F3%2C%E6%B1%82%E2%88%A0B%E5%8F%8ABC%E7%9A%84%E5%80%BC%E7%94%A8tan%2Ccos%2Csin%E6%9D%A5%E8%A7%A3)
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