设偶函数y=f(x)满足f(x)=x²-8(x≥0)则{x丨f(x-2)>0}等于?我想要下过程,
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![设偶函数y=f(x)满足f(x)=x²-8(x≥0)则{x丨f(x-2)>0}等于?我想要下过程,](/uploads/image/z/6129568-64-8.jpg?t=%E8%AE%BE%E5%81%B6%E5%87%BD%E6%95%B0y%3Df%EF%BC%88x%EF%BC%89%E6%BB%A1%E8%B6%B3f%EF%BC%88x%EF%BC%89%3Dx%26%23178%3B-8%EF%BC%88x%E2%89%A50%EF%BC%89%E5%88%99%7Bx%E4%B8%A8f%EF%BC%88x-2%EF%BC%89%EF%BC%9E0%7D%E7%AD%89%E4%BA%8E%3F%E6%88%91%E6%83%B3%E8%A6%81%E4%B8%8B%E8%BF%87%E7%A8%8B%2C)
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设偶函数y=f(x)满足f(x)=x²-8(x≥0)则{x丨f(x-2)>0}等于?我想要下过程,
设偶函数y=f(x)满足f(x)=x²-8(x≥0)则{x丨f(x-2)>0}等于?我想要下过程,
设偶函数y=f(x)满足f(x)=x²-8(x≥0)则{x丨f(x-2)>0}等于?我想要下过程,
f(x)=x²-8(x≥0),f(x-2)=(x-2)²-8,x≥2;
f(x-2)=(x-2)²-8=x²-4x-4>0,得x2+根号2,
又因为定义域要求x≥2,则结果为x>*根号2+2
因为f(x)=x^2-8,所以f(x-2)=(x-2)^2-8=x^2-4x-4
f(x-2)>0,即x^2-4x-4>0,即x<2-根号5或x>2+根号5
即{x|x<2-根号5或x>2+根号5}
f(x)=x2-8 (x》0)
f(x-2)=(x-2)2-8 (x-2》0即x》2)
f(x-2)>0
(x-2)2-8>0
解得x>*根号2+2
这个题要考虑到原函数的定义域,利用题目所给值域的范围求解定义域与原定义域做∪