lim(x→1) sin^2(x-1)/x-1 求极限

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 17:07:46
lim(x→1) sin^2(x-1)/x-1 求极限
xPMN@JCB :`Z6z ff*J1w(&5FW]LZeZyy?cu>祿z*u R~:ƃI֠-O&J&k?z?Ct0~F7Ju ($ H42%JZqg~*(ur|k.UBEd~ )chp9]m/e? <+ |K9FM`uf?|apD \"%u7YGnV ̢m !ZӔMUUuS"b@s&Y" KV5f(FYuE[dQl89U:I:A-m߷o~

lim(x→1) sin^2(x-1)/x-1 求极限
lim(x→1) sin^2(x-1)/x-1 求极限

lim(x→1) sin^2(x-1)/x-1 求极限
洛必塔法则.
原式=lim(x→1) sin(2x-2)/1=0

lim(x->1) [sin(x-1)]^2/(x-1) (0/0)
=lim(x->1) 2sin(x-1).cos(x-1)
=0

o/o型,洛必达法则
原式=lim(x→1) [2sin(x-1)cos(x-1)]/1
=lim(x→1) sin(2x-2)
=sin0
=0
望采纳