甲的速度是60m/s,乙速是67.5m/s,丙速是75m/s,甲乙在东丙在西相向而行,丙遇乙10s后遇甲,求两地距离
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![甲的速度是60m/s,乙速是67.5m/s,丙速是75m/s,甲乙在东丙在西相向而行,丙遇乙10s后遇甲,求两地距离](/uploads/image/z/6163541-53-1.jpg?t=%E7%94%B2%E7%9A%84%E9%80%9F%E5%BA%A6%E6%98%AF60m%2Fs%2C%E4%B9%99%E9%80%9F%E6%98%AF67.5m%2Fs%2C%E4%B8%99%E9%80%9F%E6%98%AF75m%2Fs%2C%E7%94%B2%E4%B9%99%E5%9C%A8%E4%B8%9C%E4%B8%99%E5%9C%A8%E8%A5%BF%E7%9B%B8%E5%90%91%E8%80%8C%E8%A1%8C%2C%E4%B8%99%E9%81%87%E4%B9%9910s%E5%90%8E%E9%81%87%E7%94%B2%2C%E6%B1%82%E4%B8%A4%E5%9C%B0%E8%B7%9D%E7%A6%BB)
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甲的速度是60m/s,乙速是67.5m/s,丙速是75m/s,甲乙在东丙在西相向而行,丙遇乙10s后遇甲,求两地距离
甲的速度是60m/s,乙速是67.5m/s,丙速是75m/s,甲乙在东丙在西相向而行,丙遇乙10s后遇甲,求两地距离
甲的速度是60m/s,乙速是67.5m/s,丙速是75m/s,甲乙在东丙在西相向而行,丙遇乙10s后遇甲,求两地距离
假设丙在X秒后遇见乙,则:丙和甲走完全程用了(10+X)秒
(60+75)*(10+X)=(67.5+75)*X
解方程得X=180
于是全程距离为(67.5+75)*180=25650