已知x-2y+1=0则2^x除以4^y乘以8=

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已知x-2y+1=0则2^x除以4^y乘以8=
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已知x-2y+1=0则2^x除以4^y乘以8=
已知x-2y+1=0则2^x除以4^y乘以8=

已知x-2y+1=0则2^x除以4^y乘以8=
x-2y+1=0
x-2y=-1
(2^x)/(4^y)*8
=(2^x)/(2^2y)*8
=(2^x)/(2^2y)*8
=2^(x-2y)*8
=2^(-1)*8
=1/2*8
=4
已知x-2y+1=0则2^x除以4^y乘以8=4