已知x²+y²-4x+y+4又1/4=0,求y的-x次方+3xy的值
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已知x²+y²-4x+y+4又1/4=0,求y的-x次方+3xy的值
已知x²+y²-4x+y+4又1/4=0,求y的-x次方+3xy的值
已知x²+y²-4x+y+4又1/4=0,求y的-x次方+3xy的值
x²+y²-4x+y+4又1/4=0
(x²-4x+4)+(y²+y+1/4)=0
(x-2)²+(y+1/2)²=0
平方项恒非负,两平方项之和=0,两平方项分别=0
x-2=0 x=2
y+1/2=0 y=-1/2
y^(-x)+3xy
=(-1/2)^(-2)+3×2×(-1/2)
=4-3
=1