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设g(x)=e的x次方 (x小于等于0),lnx (x大于0),则g[g(1/2)]=?设g(x)={e的x次方 (x小于等于0),{lnx (x大于0),则g[g(1/2)]=?
设g(x)=e的x次方 (x小于等于0),lnx (x大于0),则g[g(1/2)]=?
设g(x)={e的x次方 (x小于等于0),
{lnx (x大于0),
则g[g(1/2)]=?
设g(x)=e的x次方 (x小于等于0),lnx (x大于0),则g[g(1/2)]=?设g(x)={e的x次方 (x小于等于0),{lnx (x大于0),则g[g(1/2)]=?
首先,1/2大于零,因此g(1/2)=ln(1/2).
因为1/2小于1,故ln(1/2)小于0.
因此g(ln(1/2))=e的ln(1/2)次方=1/2
就等于1/2 一个一个地带进去就好了
1/2>0,g(1/2)=ln1/2=-ln2<0,
g[g(1/2)]=e^-ln2=1/2