Cos(180°+α)*sin（α+360°)/sin(-α-180°)*cos(-180°-α)

Cos(180°+α)*sin（α+360°)/sin(-α-180°)*cos(-180°-α) sin(α+30°)-sin(α-30°)/cosα 化简cos(540°-α)sin(α-360°)/sin(-α+180°)cos(180°+α) .[1/cos(-α)+cos(180°+ α )]/[1/sin(540°-α)+sin(360°-α)]=tan^3α 1.sin的三次方(-α)cos(2π+α)tan(-α-π)2.cos(180°+α)sin(α+360°)/sin(-α-180°)cos(-180°-α)3.sin(2π-α)cos(π+α)cos(π/2+α)sin(9π/2+α)/cos(π-α)sin(3π-α)sin(-π-α)4.已知sinα=-3/5,求cosα,tanα的值5.已知tanα=-根号下3,求 ①sin(α+180°)cos(-α)sin(-α-180°)和②sin³（-α）cos（2π+α）tan（-α-π）化简 cos(540-α)sin(α-360)/sin(-α+180)cos(180+α) cos(α+30°)cosα+sin(α+30°)sinα等于? sin(α+30°)cosα+cos(α+30°)sinα= 为什么sin(90°+α)=cosα ,cos(90°+α)=-sinα sinα-2cosα分之sinα+cosα sinαsinα+cosαcosα= 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ sin αcosβ＋cos α sin β等于? 若sinα*cosα 若sinαcosα 若sinαcosα 已知sinαcosα