设数列{an}的前n项和为sn.已知a1=a,an+1=sn-3n,n∈N*,设bn=sn-3n,且bn≠0(1) 求数列{bn} 的通项公式(2)若an+1≥an ,求实数a的取值范围.题目中an+1=sn-3n为an+1=sn+3n。之前打错了。其他条件不变
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/10 04:37:04
![设数列{an}的前n项和为sn.已知a1=a,an+1=sn-3n,n∈N*,设bn=sn-3n,且bn≠0(1) 求数列{bn} 的通项公式(2)若an+1≥an ,求实数a的取值范围.题目中an+1=sn-3n为an+1=sn+3n。之前打错了。其他条件不变](/uploads/image/z/634617-9-7.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BAsn.%E5%B7%B2%E7%9F%A5a1%3Da%2Can%2B1%3Dsn-3n%2Cn%E2%88%88N%2A%2C%E8%AE%BEbn%3Dsn-3n%2C%E4%B8%94bn%E2%89%A00%EF%BC%881%EF%BC%89+%E6%B1%82%E6%95%B0%E5%88%97%7Bbn%7D+%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%882%EF%BC%89%E8%8B%A5an%2B1%E2%89%A5an+%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4.%E9%A2%98%E7%9B%AE%E4%B8%ADan%2B1%3Dsn-3n%E4%B8%BAan%2B1%3Dsn%2B3n%E3%80%82%E4%B9%8B%E5%89%8D%E6%89%93%E9%94%99%E4%BA%86%E3%80%82%E5%85%B6%E4%BB%96%E6%9D%A1%E4%BB%B6%E4%B8%8D%E5%8F%98)
xr@_# dDx/=vp&yFΤ(5@"K:CORʗ.
ɉW )ZѓlK|pGûbE?8:;oj FŢ<1OֱOOcSs3x7=N3翐qdprMub H.jݿZ RكXʑ=
Q9mأ/r-JY;|,o- I%KJyw $U%-f1`&_`Uf\MJzb~=^