x^3+x^2y-xy^2-y^3因式分解应该等于多少丫?是不是(x+y)(x^2-y^2)?

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 12:46:30
x^3+x^2y-xy^2-y^3因式分解应该等于多少丫?是不是(x+y)(x^2-y^2)?
x)3֮3ԭ3ҭ3~:{=O;^,_tה>_dW%ndjg3? $5*+55*4mj~ \ iDhGjTAQM@( AZa"O.x>:@Γm/xڿOzؠփlȳNy6u P~qAb4Tl{::Ħi|`pR‡ @n̟2(~EHM Ɏ]zE^74!9 #

x^3+x^2y-xy^2-y^3因式分解应该等于多少丫?是不是(x+y)(x^2-y^2)?
x^3+x^2y-xy^2-y^3因式分解应该等于多少丫?是不是(x+y)(x^2-y^2)?

x^3+x^2y-xy^2-y^3因式分解应该等于多少丫?是不是(x+y)(x^2-y^2)?
x^3+x^2y-xy^2-y^3
=x^2(X+Y)-y^2(x+y)
=(x+y)(x^2-y^2)
=(x+y)(x+y)(x-y)
=(x+y)^2(x-y)
你的结果是对的,但还可以再分解呀!
(x+y)^2(x-y)才是完整的!

(x+y)^2(x-y)

原式=x^2(x+y)- y^2 (x+y)
=(x+y)(x^2 -y ^2)
=(x+y)(x+y)(x-y)
=(x+y)^2 (x-y)
因为(x^2-y^2)还能分解。