作业帮已知函数f(x)=-2asin(2x+π/6)+2a+b的定义域为[0,π/2],值域为[-5,1],求a,b的值
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![已知函数f(x)=-2asin(2x+π/6)+2a+b的定义域为[0,π/2],值域为[-5,1],求a,b的值](/uploads/image/z/639004-4-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D-2asin%282x%2B%CF%80%2F6%29%2B2a%2Bb%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%5B0%2C%CF%80%2F2%5D%2C%E5%80%BC%E5%9F%9F%E4%B8%BA%5B-5%2C1%5D%2C%E6%B1%82a%2Cb%E7%9A%84%E5%80%BC)
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已知函数f(x)=-2asin(2x+π/6)+2a+b的定义域为[0,π/2],值域为[-5,1],求a,b的值
已知函数f(x)=-2asin(2x+π/6)+2a+b的定义域为[0,π/2],值域为[-5,1],求a,b的值
已知函数f(x)=-2asin(2x+π/6)+2a+b的定义域为[0,π/2],值域为[-5,1],求a,b的值
当0≤x≤π/2时,π/6≤2x+π/6≤7π/6,那么-1/2≤sin(2x+π/6)≤1
显然a≠0,那么只有a>0和a0时,-2a
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