(a+b)²=1 ab=-6 求(a-b)² a²+b²的值
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(a+b)²=1 ab=-6 求(a-b)² a²+b²的值
(a+b)²=1 ab=-6 求(a-b)² a²+b²的值
(a+b)²=1 ab=-6 求(a-b)² a²+b²的值
(a-b)²=(a+b)²-4ab
=1²-4×(-6)
=1+24
=25
a²+b²=(a+b)²-2ab
=1²-2×(-6)
=1+12
=13