先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1
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![先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1](/uploads/image/z/646161-33-1.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BCx-4%2F%28x%26%23178%3B-1%29%E9%99%A4%E4%BB%A5x%26%23178%3B-3x-4%2F%28x%26%23178%3B%2B2x%2B1%29%2B1%2F%28x-1%29%2C%E5%85%B6%E4%B8%ADx%3D2%E5%80%8D%E6%A0%B9%E5%8F%B73%2B1)
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先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1
先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1
先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1
您好:
x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1)
=(x-4)/(x+1)(x-1)÷(x+1)(x-4)/(x+1)²+1/(x-1)
=1/(x-1)+1/(x-1)
=2/(x-1)
=2/(2√3+1-1)
=2/2√3
=1/√3
=√3/3
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