解不等式:(0.2)的x²-2x-1次方>0.04解不等式:(0.2)的(x²-2x-1)次方>0.04
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解不等式:(0.2)的x²-2x-1次方>0.04解不等式:(0.2)的(x²-2x-1)次方>0.04
解不等式:(0.2)的x²-2x-1次方>0.04
解不等式:(0.2)的(x²-2x-1)次方>0.04
解不等式:(0.2)的x²-2x-1次方>0.04解不等式:(0.2)的(x²-2x-1)次方>0.04
0.2^(x²-2x-1)>0.04=0.2²
函数y=0.2^x单调递减
x²-2x-1<2
即
x²-2x-3<0
解集为
x∈(-1,3)
(0.2)的(x²-2x-1)次方>0.2²
因为0.2<1
所以x²-2x-1<2
(x-3)(x+1)<0
所以-1
思路:首先,将其化成对数;然后,解一元二次不等式。
1:㏒以0.2为底的0.004>x²-2x-1
2:2>x²-2x-1
3:(x-3)(x+1)<0
4:解得-1