#include main() { int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;#include main(){\x05int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;\x05for(j=3;j;j--)\x05\x05switch(j)\x05{\x05\x05case 1:\x05\x05case 2:PR(*p++);break;\x05\x05case 3:PR(*(--p));\x05}}这个小
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![#include main() { int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;#include main(){\x05int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;\x05for(j=3;j;j--)\x05\x05switch(j)\x05{\x05\x05case 1:\x05\x05case 2:PR(*p++);break;\x05\x05case 3:PR(*(--p));\x05}}这个小](/uploads/image/z/654703-7-3.jpg?t=%23include+%26%238203%3Bmain%28%29+%7B+int+j%2Ca%5B+%5D%3D%7B1%2C3%2C5%2C7%2C9%2C11%2C13%2C15%7D%2C%2Ap%3Da%2B5%3B%23include+main%28%29%7B%5Cx05int+j%2Ca%5B+%5D%3D%7B1%2C3%2C5%2C7%2C9%2C11%2C13%2C15%7D%2C%2Ap%3Da%2B5%3B%5Cx05for%28j%3D3%3Bj%3Bj--%29%5Cx05%5Cx05switch%28j%29%5Cx05%7B%5Cx05%5Cx05case+1%3A%5Cx05%5Cx05case+2%3APR%28%2Ap%2B%2B%29%3Bbreak%3B%5Cx05%5Cx05case+3%3APR%28%2A%28--p%29%29%3B%5Cx05%7D%7D%E8%BF%99%E4%B8%AA%E5%B0%8F)
#include main() { int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;#include main(){\x05int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;\x05for(j=3;j;j--)\x05\x05switch(j)\x05{\x05\x05case 1:\x05\x05case 2:PR(*p++);break;\x05\x05case 3:PR(*(--p));\x05}}这个小
#include main() { int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;
#include
main()
{
\x05int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;
\x05for(j=3;j;j--)
\x05\x05switch(j)
\x05{
\x05\x05case 1:
\x05\x05case 2:PR(*p++);break;
\x05\x05case 3:PR(*(--p));
\x05}
}
这个小弟遇到了难题,
#include main() { int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;#include main(){\x05int j,a[ ]={1,3,5,7,9,11,13,15},*p=a+5;\x05for(j=3;j;j--)\x05\x05switch(j)\x05{\x05\x05case 1:\x05\x05case 2:PR(*p++);break;\x05\x05case 3:PR(*(--p));\x05}}这个小
题目不完整 PR是什么玩意