设函数f(x)=(x(1-x)^5)+1/2∫上限1下限0 f(x)dx,求f(x)
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![设函数f(x)=(x(1-x)^5)+1/2∫上限1下限0 f(x)dx,求f(x)](/uploads/image/z/6598157-5-7.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3D%28x%281-x%29%5E5%29%2B1%2F2%E2%88%AB%E4%B8%8A%E9%99%901%E4%B8%8B%E9%99%900+f%28x%29dx%2C%E6%B1%82f%28x%29)
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设函数f(x)=(x(1-x)^5)+1/2∫上限1下限0 f(x)dx,求f(x)
设函数f(x)=(x(1-x)^5)+1/2∫上限1下限0 f(x)dx,求f(x)
设函数f(x)=(x(1-x)^5)+1/2∫上限1下限0 f(x)dx,求f(x)
如图