3x^3-x=1,求6x^3+7x^2-5x+29.十万火急~
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3x^3-x=1,求6x^3+7x^2-5x+29.十万火急~
3x^3-x=1,求6x^3+7x^2-5x+29.十万火急~
3x^3-x=1,求6x^3+7x^2-5x+29.十万火急~
3x^3-x=1
=6x^3+7x^2-5x+29
=(6x^3-2x)+7x^2-3x+29
=2(3x^3-x)+7x^2-3x+29
=7x^2-3x+29+2
=7x^2-3x+31
3x^3-x=1
=6x^3+7x^2-5x+29
=(6x^3-2x)+7x^2-3x+29
=2(3x^3-x)+7x^2-3x+29
=7x^2-3x+29+2
=7x^2-3x+31
给方程3x³-x=1两边乘以2得:
6x³-3x=2把乘2后的方程代入原代数式中得:
6x³+7x²-5x+29
=6x³-3x+7x²-2x+29
=2+7x²-2x+29
=7x²-2x+31
3x^3-x=1
=6x^3+7x^2-5x+29
=(6x^3-2x)+7x^2-3x+29
=2(3x^3-x)+7x^2-3x+29
=7x^2-3x+29+2
=7x^2-3x+31
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