先化简再求值:(1-1/x)/(x^2-2x+1)/(x^2-1),其中x=根号2

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 12:04:08
先化简再求值:(1-1/x)/(x^2-2x+1)/(x^2-1),其中x=根号2
x){gu OzmlzڰJPPBS_"HרB4yںɎ|ڿ&HB l Ҷ@~E>P.B}dIPa?ba uT.L!$0yv=`

先化简再求值:(1-1/x)/(x^2-2x+1)/(x^2-1),其中x=根号2
先化简再求值:(1-1/x)/(x^2-2x+1)/(x^2-1),其中x=根号2

先化简再求值:(1-1/x)/(x^2-2x+1)/(x^2-1),其中x=根号2
(1-1/x)/(x^2-2x+1)/(x^2-1)
=[(x-1)/x]/[(x+1)(x+1)]/[(x+1)(x-1)]
=[(x-1)/x]/[(x+1)/(x-1)]
=1/x/[(x+1)
=1/[x(x+1)]
=1/(2+根号2)
=(2-根号2)/[(2+根号2)(2-根号2)]
=(2-根号2)/2