函数y=y1+y2且y1=2x+m,y2=[1/(m-1)]x+3.(1)若y1与y2图像的焦点纵坐标为4 求y关于x的解析(2函数y=y1+y2且y1=2x+m,y2=[1/(m-1)]x+3.(1)若y1与y2图像的焦点纵坐标为4 求y关于x的解析式(2)若(1)中函数y的
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![函数y=y1+y2且y1=2x+m,y2=[1/(m-1)]x+3.(1)若y1与y2图像的焦点纵坐标为4 求y关于x的解析(2函数y=y1+y2且y1=2x+m,y2=[1/(m-1)]x+3.(1)若y1与y2图像的焦点纵坐标为4 求y关于x的解析式(2)若(1)中函数y的](/uploads/image/z/6605867-11-7.jpg?t=%E5%87%BD%E6%95%B0y%3Dy1%2By2%E4%B8%94y1%3D2x%2Bm%2Cy2%3D%5B1%2F%28m-1%29%5Dx%2B3.%EF%BC%881%EF%BC%89%E8%8B%A5y1%E4%B8%8Ey2%E5%9B%BE%E5%83%8F%E7%9A%84%E7%84%A6%E7%82%B9%E7%BA%B5%E5%9D%90%E6%A0%87%E4%B8%BA4+%E6%B1%82y%E5%85%B3%E4%BA%8Ex%E7%9A%84%E8%A7%A3%E6%9E%90%EF%BC%882%E5%87%BD%E6%95%B0y%3Dy1%2By2%E4%B8%94y1%3D2x%2Bm%2Cy2%3D%5B1%2F%28m-1%29%5Dx%2B3.%EF%BC%881%EF%BC%89%E8%8B%A5y1%E4%B8%8Ey2%E5%9B%BE%E5%83%8F%E7%9A%84%E7%84%A6%E7%82%B9%E7%BA%B5%E5%9D%90%E6%A0%87%E4%B8%BA4+%E6%B1%82y%E5%85%B3%E4%BA%8Ex%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%882%EF%BC%89%E8%8B%A5%EF%BC%881%EF%BC%89%E4%B8%AD%E5%87%BD%E6%95%B0y%E7%9A%84)
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