已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/04 15:49:01
xj@_%J&\]f.n2q`ʟڅ&4s'+8>q>=IQ
LL!K l%MzF A7U,ЛiVo5fWx3[I`%N$+s|v&mu{텙K/I
Mz7zvx=N^,ίԼ#e
已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
已知:x/2=y/3=z/4,求(x2+y2-z2-2xy)/(x2-y2+z2-2xz)除以(x2-y2-z2+2yz)/(x2+y2-z2+2xy)
设 x/2=y/3=z/4 = k
则 x = 2k,y=3k,z=4k,代入你要的式子就可以算出结果,因为式子中都是2次方,最后k可以消掉.